WAEC Physics Practical Solution Questions and Answer – MAY/JUNE 2019 Expo Runz.
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In a tabular form
20.0, 30.0, 40.0, 50.0, 60.0
36.61, 33.66, 31.32, 28.62, 25.93
Under T = t/20(s)
1.8305, 1.6830, 1.5660, 1.4310, 1.2965
3.3507, 2.8325, 2.4524, 2.0478, 1.6809
Slope s = ΔT²/Δy
S = 4 - 2.5/0 - 39
S = 1.5/-39
S = -0.0385
Intercept, C = 4.0
SR = c
R = c/s = 4/-0.0385 = -103.9
(i) I ensured that the retort stand was well clamped.
(ii) I avoided error due to parallax when reading the metre rule.
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Draw the diagram
(α) K.E is maximum
(β) acceleration is maximum
Period, T = 2π√m/k
Given : weight, W = 120N
Mass = w/g = 120/10 = 12
T = 45
π = 3.142
4 = 2(3.142)√12/k
0.6365 = √12/k
Square both sides
0.405 = 12
K = 12/0.405 = 29.6
E.m.f, E = 3.00v
In a tabular form
2.0, 5.0, 10.0, 12.0, 15.0, 20.0
0.86, 0.62, 0.43, 0.38, 0.32, 0.25
1.1628, 1.6129, 2.3256, 2.6316, 3.1250, 4.0000
Slope s = ΔR/Δv-¹
=17.5 - 4.25/3.5 - 1.5
Intercept, C = -5.75
S = Roα
6.625 = 0.85(α)
α = 6.625/0.85 = 7.79
C = -(Ro + β)
= -5.75 = -(0.85 + β)
β = 5.75 - 0.85
β = 4.9
(i) I ensured tight connections.
(ii) I avoided error due to parallax when reading the voltmeter.
Vab = 12 - 8 = 4v
Rab = 4×5/4+5 = 20/9ohms
Iab = Vab/Rab = 4/20/9 = 4 ×9/20 = 9/5
Power = I²ab Rab
=1.8² * 20/9
Current in line = power/voltage = 3600/240
Circuit breaker remain closed because current in line is less than 20A
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(i) I avoided parallax error when taking readings from the voltmeter
(ii) I ensured that the key was opened when reading is not been taking
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: WAEC 2019 Physics Practical Solution Answer – May/June Expo
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